A man stands before a large wall at a distance of $50.0 m$ and claps his hand in regular intervals such that the echo of a clap merges with the next clap. If he has to clap $10$ times in $3$ seconds then, calculate the velocity of sound in air.

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Solution

Each clap must occur at the instant the echo of the last one returns.
Claps occur every $\frac{(3 s e c o n d s)}{5}$ = $0.6 s e c o n d$ .

The sound travels to the wall and back,

or $100 + 100 = 200 m$ in this time $0.6 s e c$
Hence velocity = $\frac{D}{t}$

$v$ = $\frac{(200 m)}{(0.6 s e c)}$

= $333.33 m / s e c .$

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