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Byju's Answer
Standard IX
Physics
Reflection of Sound
A man stands ...
Question
A man stands between two cliffs and fires a gun. He hears two successive echoes after 3s and 5s. Find the distance between the two cliffs ?
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Solution
distance of the person from the rearer cliff
d
1
=
V
×
t
2
=
330
×
3
2
=
495
m
Distance of the person from the farther cliff
d
2
=
V
×
t
2
=
330
×
5
2
=
825
m
Toatl distance beween two cliffs
=
d
1
+
d
2
=
495
+
825
=
1320
m
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Q.
A man is standing between two parallel cliffs and fires a gun. If he hears first and second echoes after 1.5 s and 3.5 s respectively, the distance between the cliffs is (Velocity of sound in air =
340
m
s
−
1
)
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