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Question

A man stands in between two cliffs and fires a gun. He hears two successive echoes after 3 sec and 5 sec. What is the distance between two cliffs? (speed of sound = 330ms1

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Solution

For the first echo, If S1 be the distance of the man from one cliff, the sound travels distance in 3 sec is 2S1.
For the second echo, if S2 be the distance of the man from another cliff, the sound travels distance in 5 sec is 2S2
Using formula, S=vt,
2S1=330(3) or S1=495m and 2S2=330(5) or S2=825m
The distance between the cliffs =S1+S2=495+825=1320m

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