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Question

A man started his job with a certain monthly salary and earned a fixed increment every year. If his salary was Rs.4500 after 5 years of service and Rs.5550 after 12 years of service, what was his starting salary and what was his annual increment.

A
Starting salary =Rs.2550 and annual increment =Rs.180
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B
Starting salary =Rs.3750 and annual increment =Rs.150
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C
Starting salary =Rs.3500 and annual increment =Rs.150
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D
Starting salary =Rs.4050 and annual increment =Rs.120
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Solution

The correct option is A Starting salary =Rs.3750 and annual increment =Rs.150
Let man's initial monthly salary be Rs.x and annual increment be Rs.y
Then According to the problem
After 5 years salary wil become
x+5y = 4500........(1)
After 12 years salary will be
x+12y = 5550........(2)
Hence we get equations
x+5y = 4500........(1)
x+12y = 5550........(2)
Subtracting eq (1) from eq(2)
7y = 1050
y=10507=150
Putting value of y in eq(1) we get x = 3750
Solving these two equations, we get x = Rs.3750, y = Rs.150
Hence starting salary = Rs.3750 and annual increment = Rs.150

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