Question

A man starts his job with a certain monthly salary and earns a fixed increment every year. If his salary was Rs $1500$ after $4$ year of service and Rs $1800$ after $10$ years of service, what was his starting salary and what is the annual increment?

Answer 1

Let the starting salary of the man be Rs. $x$ and the fixed annual increment be Rs. $y$. Then,

Salary after $4$ years of service $=$Rs. $(x+4y)$
Salary after $10$ years of service $=$Rs. $(x+10y)$

$\therefore x+4y=1500$ (i)
$x+10y=1800$ (ii)

Substracting equation (i) from equation (ii), we get
$6y=300\Rightarrow y=50$

Putting $y=50$ in equation (i), we get $x=1300$.

Hence the starting salary was Rs. $1300$ and annual increment is Rs. $50$.