54
Question
A man starts repaying a loan as first installment of Rs. 100. If he increases the installment by Rs 5 every month, what amount he will pay in the 30 th installment?
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Solution
The first installment of the loan is Rs 100.
The second installment of the loan is Rs 105 and so on.
The amount that the man repays every month forms an arithmetic progression.
The A.P. is 100 , 105 , 110 … .
Let the first term and common difference of the A.P. be a and d respectively.
The formula for n t h terms in an A.P. is given by,
A n = a + ( n − 1 ) d
Substitute the values in the above expression.
A 30 = 100 + ( 30 − 1 ) × 5 = 100 + 29 × 5 = 100 + 145 = 245
Thus, the amount to be paid in the 30 t h installment is Rs 245 .
The first installment of the loan is Rs 100.
The second installment of the loan is Rs 105 and so on.
The amount that the man repays every month forms an arithmetic progression.
The A.P. is
Let the first term and common difference of the A.P. be
The formula for
Substitute the values in the above expression.
Thus, the amount to be paid in the
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