CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A man swims from a point A on one bank of a river of width 100 m . When he swims perpendicular to the water current, he reaches the other bank 50 m away from point B downstream. The angle to the bank at which he should swim, to reach the directly opposite point B on the other bank is (in both the cases speed of man with respect to river is same)

A
80 with the direction of flow of river
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
110 with the direction of flow of river
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
120 with the direction of flow of river
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
150 with the direction of flow of river
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 120 with the direction of flow of river
Let vmw be the velocity of man w.r.t river and vw be the velocity of river.

From figure (a), we get
tanθ=vwvmw=50100=12

or vmw=2vw

Using Figure (b), we can say
sinα=vwvmw=vw2vw=12

or α=30
Angle with the direction of flow, α+90=120

So, it is 120 with the direction of flow of river.

flag
Suggest Corrections
thumbs-up
6
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion in 2D
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon