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Question

# A man swims from a point A on one bank of a river of width 100 m . When he swims perpendicular to the water current, he reaches the other bank 50 m away from point B downstream. The angle to the bank at which he should swim, to reach the directly opposite point B on the other bank is (in both the cases speed of man with respect to river is same)

A
80 with the direction of flow of river
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B
110 with the direction of flow of river
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C
120 with the direction of flow of river
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D
150 with the direction of flow of river
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Solution

## The correct option is C 120∘ with the direction of flow of riverLet vmw be the velocity of man w.r.t river and vw be the velocity of river. From figure (a), we get tanθ=vwvmw=50100=12 or vmw=2vw Using Figure (b), we can say sinα=vwvmw=vw2vw=12 or α=30∘ Angle with the direction of flow, α+90∘=120∘ So, it is 120∘ with the direction of flow of river.

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