CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A man throws a ball weighing 200 g vertically upwards with a speed of 10m/s. Its momentum at the highest point of its flight will be:


A

2 kg. m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2000 kg.m/s

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Insufficient data to find the momentum

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

zero

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is C: zero

At the highest point, velocity of ball becomes zero.

Hence, the momentum,

p = mv = m*0 = 0

Momentum also becomes zero.


flag
Suggest Corrections
thumbs-up
17
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equations of Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon