Question

A man tosses two different coins (one of the Rs $2$ and another of Rs $5$) simultaneously. What is the probability that he gets at most one head?

Answer 1

We know that,

When two coins are tossed simultaneously, the possible outcomes are $(H,H),(H,T),(T,H),(T,T)$

So, $n\left(S\right)=4$

The outcomes favorable to the event E, ‘at most one head’ are $(T,H),(H,T),(T,T)$

So, the number of outcomes favorable to E is $3=n\left(E\right)$

Hence,$P\left(E\right)=n\left(E\right)/n\left(S\right)=3/4$