A man travels 1mile due east, 5mile due south, 2mile due east and finally 9miles due north. How far is the starting point?
A
3miles
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B
5miles
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C
4miles
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D
between 5miles and 9miles
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Solution
The correct option is B5miles Net eastward displacement =1+2=3 miles Net northward displacement =−5+9=4 miles Net displacement →d=3^i+4^j ∣∣→d∣∣=√32+42=5 miles