A man travels 1 mile due east, then 5 miles due south, then 2 miles due east and finally 9 miles due north. His displacement is
A
3 miles
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B
5 miles
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C
4 miles
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D
between 5 and 9 miles
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Solution
The correct option is B5 miles Consider the initial position is at the origin , and North is + Y axis,South being negative Y axis, East is positive X axis and West is negative X axis. Then starting from origin , After 1 miles due east,his coordinates are (1,0) After 5 miles due south ,his coordinates become (1,-5) After 2 miles due east , his coordinates are ( 1+2 ,-5) i.e ( 3,-5) After 9 miles due north , his coordinates are (3,-5+9) i.e ( 3,4) Hence , distance from the initial position is √32+42=5