A man travels 3/8 of his journey by train, 3/5 of his journey by bus and walks the rest of the distance. If he walks 2km, how much distance did he travel by bus

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Solution

$D e a r s t u d e n t, S o l . L e t t o t a l j o u r n e y b e x k m . J o u r n e y b y t r a i n = \frac{3 x}{8} k m J o u r n e y b y b u s = \frac{2 x}{5} k m J o u r n e y b y w a l k = x - (\frac{3 x}{8} + \frac{2 x}{5}) = x - (\frac{15 x + 16 x}{40}) = x - \frac{31 x}{40} = \frac{9 x}{40} k m A c c o r d i n g t o q u e s t i o n, \frac{9 x}{40} = \frac{7}{2} [3 \frac{1}{2} = \frac{7}{2}] 18 x = 280 x = \frac{280}{18} = 15.56 k m N o w, J o u r n e y b y t a x i = 15.56 \times \frac{3}{8} = 5.84 k m (a p p r o x .) R e g a r d s$

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