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Question

A man travels along a straight line. He covers the first half distance with constant velocity v1 and the next half distance with constant velocity v2. The average velocity of man will be :

A
v1+v22
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B
v=2v1v2v1+v2
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C
(v1v2)1/2
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D
(v2v1)1/2
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Solution

The correct option is C v=2v1v2v1+v2
Let Total distance = D
For, distance , D2,V=V1
t1=D/2V1=D/2v1
For wxt D2,V=V2
t2=D/2V2=D/2v2
average velocity = TotaldistancetravelledTotaltime
DD2V1+D2V2=2V1V2V1+V2
average velocity = 2V1V2V1+V2

1166821_1336115_ans_6965feb313d14cef883ecc59ba113cac.jpg

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