A man uses a crowbar of length $1.5 m$ to raise a load of $75 k g f$ by putting a sharp edge below the bar at a distance $1 m$ from his hand. Calculate the mechanical advantage.

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Solution

The correct option is A $2$
Load $= 75 k g f$
Length of crowbar $= 1.5 m$
Effort arm $= 1 m$
So, Load Arm $= Length of crowbar - Effort arm$

$\Rightarrow 1.5 - 1 = 0.5 m$
Mechanical Advantage $= \frac{Effort Arm}{Load Arm} = \frac{1}{0.5} = 2$

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A man uses a crowbar of length 1.5 m to raise a load of 75 kgf by putting a sharp edge below the bar at a distance 1 m from his hand. State the kind of lever and calculate the effort needed.

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A man uses a crowbar of length 1.5m to raise a load of 75kgf by putting a sharp edge below the bar at a distance 1m from his hand. Calculate the mechanical advantage.

The correct option is A 2Load =75kgfLength of crowbar =1.5mEffort arm =1mSo, Load Arm =Length of crowbar - Effort arm⇒1.5−1=0.5mMechanical Advantage =Effort ArmLoad Arm=10.5=2

A man uses a crowbar of length $1.5 m$ to raise a load of $75 k g f$ by putting a sharp edge below the bar at a distance $1 m$ from his hand. Calculate the mechanical advantage.

The correct option is A $2$
Load $= 75 k g f$
Length of crowbar $= 1.5 m$
Effort arm $= 1 m$
So, Load Arm $= Length of crowbar - Effort arm$

$\Rightarrow 1.5 - 1 = 0.5 m$
Mechanical Advantage $= \frac{Effort Arm}{Load Arm} = \frac{1}{0.5} = 2$