A man uses a crowbar of length 2.5 m to raise a load of 75 kgf by putting a sharp edge below the bar at a distance 1 m from his hand. State the kind of lever used and calculate the effort needed.

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Solution

Load arm = 2.5 – 1.0 = 1.5 m

Effort arm = 1m

Mechanical Advantage = $\frac{1.5}{1}$ = 1.5

Mechanical Advantage = $\frac{L o a d}{E f f o r t}$

1.5 = $\frac{75 k g f}{E}$

E = $\frac{75}{1.5}$ = 50 kgf, Class I Lever

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A man uses a crowbar of length 2.5 m to raise a load of 75 kgf by putting a sharp edge below the bar at a distance 1 m from his hand. State the kind of lever used and calculate the effort needed.

Load arm = 2.5 – 1.0 = 1.5 m Effort arm = 1m Mechanical Advantage = 1.51 = 1.5 Mechanical Advantage = LoadEffort 1.5 = 75kgfE E = 751.5 = 50 kgf, Class I Lever

Load arm = 2.5 – 1.0 = 1.5 m

Effort arm = 1m

Mechanical Advantage = $\frac{1.5}{1}$ = 1.5

Mechanical Advantage = $\frac{L o a d}{E f f o r t}$

1.5 = $\frac{75 k g f}{E}$

E = $\frac{75}{1.5}$ = 50 kgf, Class I Lever