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Question

A man walked 3 metre towards North, turned West and walked 2 metre then turned North and walked 1 metre and finally turned East and walked 5 metre. How far is he from the starting point ?

A
5 metre
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B
8 metre
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C
10 metre
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D
12 metre
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Solution

The correct option is B 5 metre
Let us consider a Cartesian plane thinking positive X-axis as South,
Negative x axis as North, Positive Y-axis as East and Negative as West.
A man walked along negative X-axis 3 m and then parallel to negative Y-axis he walked 2 m.
And then parallel to negative X-axis he walked 1 m and finally walked 5 m parallel to positive Y-axis and he has coordinates of (4,3).
He makes right angle triangle with base AC=4, side AB=3 and hypotenuse BC.
by Pythagoras theorem,
BC2=AB2+AC2
BC2=32+42
BC=5.
Hence from origin he is at distance of 5 m.
Thus, option A is the correct.

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