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Question

A man walked 3 metre towards North, turned West and walked 2 metre then turned North and walked 1 metre and finally turned East and walked 5 metre. How far is he from the starting point ?


A
5 metre
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B
8 metre
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C
10 metre
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D
12 metre
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Solution

The correct option is B $$5$$ metre
Let us consider a Cartesian plane thinking positive X-axis as South, 
Negative x axis as North, Positive Y-axis as East and Negative as West.
A man walked along negative X-axis $$3$$ m and then parallel to negative Y-axis he walked $$2$$ m.
And then parallel to negative X-axis he walked $$1$$ m and finally walked $$5$$ m parallel to positive Y-axis and he has coordinates of $$(-4,3)$$.
He makes right angle triangle with base AC=4, side AB=3 and hypotenuse BC.
$$\therefore$$ by Pythagoras theorem,
$$BC^2=AB^2+AC^2$$
$$\implies$$ $$BC^2=3^2+4^2$$
$$\therefore$$ $$BC=5$$.
Hence from origin he is at distance of 5 m.
Thus, option A is the correct.

313531_319906_ans_03ff29bba23f4818a5b358801016bac2.png

Logical Reasoning

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