The correct option is B
$$5$$ metreLet us consider a Cartesian plane thinking positive X-axis as South,
Negative x axis as North, Positive Y-axis as East and Negative as West.
A man walked along negative X-axis $$3$$ m and then parallel to negative Y-axis he walked $$2$$ m.
And then parallel to negative X-axis he walked $$1$$ m and finally walked $$5$$ m parallel to positive Y-axis and he has coordinates of $$(-4,3)$$.
He makes right angle triangle with base AC=4, side AB=3 and hypotenuse BC.
$$\therefore$$ by Pythagoras theorem,
Hence from origin he is at distance of 5 m.
Thus, option A is the correct.