1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A man walks 30 m towards north, then 20 m, towards east and in the last 30√2m towards south west. The displacement from origin is

A
10 m towards west
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
10 m towards east
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
602m, towards north west
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
602m, towards east north
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is A 10 m towards westDisplacement is the shortest distance between the initial and final position of the particle.From the above figure,→AB=30m →BC=20m→CD=30√2mΔ(OCD) is right angle triangle,By Pythagoras theorem,(DC)2=(OC)2+(DO)2(30√2)2=(OC)2+(30)2OC=30m. . . . . .(1)OD=DA+OA=30mDA=30m−20m=10mDA=10mThe displacement from the origin is 10m towards the west.The correct option is A.

Suggest Corrections
2
Join BYJU'S Learning Program
Related Videos
Visualisation of Pythagoras' Theorem
MATHEMATICS
Watch in App
Join BYJU'S Learning Program