Question

A man walks $4\frac{1}{3}$ $km$ in one $hour$ . What distance will he walk in $2\frac{1}{3}$ hours?

Answer 1

Step1. Convert the given mixed fraction into an improper fraction.

$4\frac{1}{3}=\frac{\left(4\times 3\right)+1}{3}$

$=\frac{13}{3}$

$2\frac{1}{3}=\frac{\left(2\times 3\right)+1}{3}$

$=\frac{7}{3}$

Step 2. Find the speed of a man that covers $4\frac{1}{3}$ $km$ in one $hour$.

Given : the distance covered by the man, $D=4\frac{1}{3}$ $=$ $\frac{13}{3}$ $km$.

time is taken by man to cover the distance $\frac{13}{3}$ $km$, $T$ $=$$1$$hour$.

Apply the formula, $speed$ $=$ $\frac{dis\tan ce}{time}$

Speed of man, $S$ $=$ $\frac{D}{T}$ $=\frac{13}{3}÷1$

$S$ $=$ $\frac{13}{3}$ $\frac{km}{hour}$

Step 3. Find the distance that man will walk in $2\frac{1}{3}$ hours.

Apply the formula, $speed$ $=$ $\frac{dis\tan ce}{time}$ .

The distance will man cover in $2\frac{1}{3}$ hours, $D$ $=$ $speed\times time$ $=$ $\frac{13}{3}\times 2\frac{1}{3}$

$D$ $=\frac{13}{3}$ $\times$ $\frac{7}{3}$ $=\frac{91}{9}$ $km$

Hence, the man will walk the $\frac{91}{9}km$ in $2\frac{1}{3}hour$.