A man walks on a straight road from his home to a market 2.5 km away with a speed of $5 k m h^{- 1}$ . Finding the market closed, he instantly turns and walks back home with a speed of $7.5 k m h^{- 1}$ . What is the magnitude of average velocity?

10 m/s

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20 m/s

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35 m/s

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0 m/s

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Solution

The correct option is D 0 m/s
Average velocity = Total Displacement/ Total Time $= 0 m / s^{2}$
Because, at the end displacement = 0 m.

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