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Normal Reaction

A man weighin...

Question

A man weighing $1500 N$ exerts a pressure of $105 N / m^{2}$ on the ground. Calculate his area of contact with the ground.

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Solution

$w = 1500 N$
$P = 105 N / m^{2} = \frac{w}{A}$
$P = 105 = \frac{1500}{A}$
$A = \frac{1500}{105} = [\frac{100}{7}] m^{2}$

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