Question

A man weighing $50$ Kg carries a load of $10$ Kg to the top of the building in $4$ minutes. the work done by the man is $6\times {10}^{4}J$. If he carries the same load in $8$ minutes, the work done by the man will be :

• A. $1.5\times {10}^4$ J
• B. $3\times {10}^4$ J
• C. $6\times {10}^4$ J
• D. $12\times {10}^4$ J

Answer 1

The correct option is C $6\times {10}^4$ J

Work done. does not depend on time hence will be equal.