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Question

A man weighing 60 kg stands on the horizontal platform fixed to a spring balance. The platform starts executing simple harmonic motion of amplitude 0.1 m and frequency 2π Hz. Which of the following statements is correct?
[Assume the man is always in contact with the platform and spring balance has only vertical motion]


A
The spring balance reads the weight of man as 60 kg.
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B
The spring balance reading fluctuates between 60 kg and 70 kg.
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C
The spring balance reading fluctuates between 50 kg and 60 kg.
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D
The spring balance reading fluctuates between 50 kg and 70 kg.
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Solution

The correct option is D The spring balance reading fluctuates between 50 kg and 70 kg.
The maximum force acting on the body executing simple harmonic motion is
Fmax=|kA|=mω2A=m×(2πf)2A
From the data given in the question,
F=60×(2π×2π)2×0.1=96 N or 969.810 kgf
This force always acts towards the mean position.



Case -I :
In Equilibrium position , As shown in the figure, Normal reaction force balances the weight of the man
So, the spring balance reading measures 60 kg.
Case -II :
At Upper extreme position , The force Fmax is acting downwards (towards mean position). So a pseudo force acts on it in the opposite direction.
From FBD,
N+Fmax=mgN=mgFmax=6010=50 kgf
The reaction of the force on the platform is away from the mean position. It reduces the weight of man at upper extreme i.e. Net weight =50 kgf.
Case- III :
At lower extreme position, the force Fmax is acting upwards (towards mean position). So, a pseudo force acts on it in the opposite direction.
From FBD,
N=mg+Fmax=60+10=70 kgf
The reaction of the force on the platform is away from the mean position. This force adds to the weight at lower extreme position i.e. net weight =70 kgf.
Therefore, the reading of the weight recorded by the spring balance flutuates between 50 kgf and 70 kgf.
Thus, option (d) is the correct answer.

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