A man weighs 600 N on the equator, but when he moves to pole he finds a slight increase in his weight. This is because of the of Earth.

change in radius

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Solution

The correct option is A change in radius
On Earth, acceleration due to gravity $g = \frac{G M}{R^{2}}$ , where 'G' is the gravitational constant, 'M' is the mass of Earth and 'R' is the radius of Earth.
Weight is the force due to gravity i.e., mg, where 'm' is the mass of the body and 'g' is the acceleration due to gravity.
Since Earth is an imperfect sphere, its 'R' is smaller at poles than at equator. The value of 'g' increases at poles as 'g' is inversely proportional to 'R'. Hence, the weight of the body also increases.

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