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Standard VIII

Physics

Normal Force

A man weighs ...

Question

A man weighs 80 kg He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $5 m / s^{2} .$ What would be the reading on the scale ? $(g = 10 m / s^{2})$

Z e r o

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400 N

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800 N

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1200 N

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Solution

The correct option is D $1200 N$
The reading on scale would be
$w = M (g + a)$
$w = 80 (10 + 5)$
$w = 1200 N$
Hence,
Option $(D)$ is correct answer.

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A man weighs 80 kg He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5m/s2. What would be the reading on the scale ? (g=10m/s2)

The correct option is D 1200NThe reading on scale would be w=M(g+a)w=80(10+5)w=1200NHence,Option (D) is correct answer.

A man weighs 80 kg He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $5 m / s^{2} .$ What would be the reading on the scale ? $(g = 10 m / s^{2})$

The correct option is D $1200 N$
The reading on scale would be
$w = M (g + a)$
$w = 80 (10 + 5)$
$w = 1200 N$
Hence,
Option $(D)$ is correct answer.