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Standard XII

Physics

1st Equation of Motion

A man weighs ...

Question

A man weighs $80 k g$ . He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $5 m / s^{2}$ . What would be the reading on the scale? ( $g = 10 m / s^{2}$ )

1200 N

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400 N

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100 N

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Solution

The correct option is A $1200 N$
For a lift going upward, reading on the weighing scale, $N$ , is expressed as:
$N - M g = M a$
or, $N = M (a + g) = 80 (5 + 10) = 1200 N$

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A man weighs 80 kg. He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $5 m / s^{2}$ . What would be the reading on the scale. $(g = 10 m / s^{2})$

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A man weighs 80kg. He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of 5m/s2. What would be the reading on the scale? (g=10m/s2)

The correct option is A 1200NFor a lift going upward, reading on the weighing scale, N, is expressed as:N−Mg=Maor, N=M(a+g)=80(5+10)=1200N

A man weighs $80 k g$ . He stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of $5 m / s^{2}$ . What would be the reading on the scale? ( $g = 10 m / s^{2}$ )

The correct option is A $1200 N$
For a lift going upward, reading on the weighing scale, $N$ , is expressed as:
$N - M g = M a$
or, $N = M (a + g) = 80 (5 + 10) = 1200 N$