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Application of Formula of CI

A man weight ...

Question

A man weight 72 kg. His wife 's weight is 25% less than his . if their son weight 10% more than his mother. find the son's weight .

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Solution

Given: Man Weight $= 72 k g$
Wife's weight $= 72 - 25 % o f 72$
$= 72 - 18$
$= 54 k g$
Son's Weight $= 54 k g + 10 %$ of mother's weight
$= 54 + 10 % o f 54$
$= 54 + 5.4$
$= 59.4 k g$
Son's weight $= 59.4 k g$

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