A man who makes a profit of $25 p . c .$ by selling tea at $R s . 4.25$ a kg lowers his ratio so as to gain only $17 P$ per kg. In what ratio must his sales increase so that the profit may be the same as before?

4

times

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5

times

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7

times

No worries! We‘ve got your back. Try BYJU‘S free classes today!

85

times

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $5$ times
$125$ % $C . P . = R s . 4.25$
$∴$ C.P. of tea per kg $= R s . \frac{4.25 \times 100}{125}$
$= R s . 3.40$
Gain on $1 k g = 85 P$
Quantity of tea sold to recover $85 P$ . when gain is $17 P$ per kg $= \frac{85}{17} = 5 k g$
Thus he must increase sales $5$ times.

Suggest Corrections

Similar questions

120

20 %

30 %

60

65

68.20

In what ratio a grocer mix two varieties of tea worth Rs. 60 per kg and Rs. 65 per kg so that by selling mixture at Rs. 68.20 kg he may gain 10%?

Join BYJU'S Learning Program