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Question

A man wishes to cross a river and come back to original position by swimming minimum distance. If the width of the river is 50 m, speed of river is 2 m/s and velocity of man with respect to river is 4 m/s, then time taken by man to come back to original position is

A

50 3 sec
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B

502 sec
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C

25 sec
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D

253 sec
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Solution

The correct option is A
50 3 sec
For minimum distance
vr=vm sin θ2=4 sin θ
vm cos θ=4 cos 30=23
so time t=2wvm cos θ=2×5023=503

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