You visited us 1 times! Enjoying our articles? Unlock Full Access!

Heat

A man wishes ...

Question

A man wishes to fit an aluminium ring on steel rod of 1 cm diameter and found it is 0.01 cm smaller in diameter. How much should the on temperature be raised before it just slips on the
$(α_{A} = 25 \times 10^{- 6} /^{o} C;$ $10 \times 10^{- 6} /^{o} C)$

40^{o} C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

50^{o} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

25^{o} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

60^{o} C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $40^{o} C$
$l_{2} = l_{1} (1 + α_{A} Δ T)$

$l_{2} = l_{1} + l_{1} α_{A} Δ T$

$\frac{l_{2} - l_{1}}{l_{1}} = α_{A} Δ T$

$\frac{0.01 \times 10^{- 2}}{1 \times 10^{- 2} \times 25 \times 10^{- 6}} = Δ T$

$Δ T = 40^{0} C$

Suggest Corrections

Similar questions

25^{\circ} C

25^{\circ} C

α_{s t e e l} = 12 \times 10^{- 6} K^{- 1}

α_{b r a s s} = 18 \times 10^{- 6} K^{- 1}

1.20 m

1.0 c m

= 12 \times 10^{- 6} /^{\circ} C

25^{\circ} C

25^{\circ} C

α_{s t e e l} = 12 \times 10^{- 6} K^{- 1}

α_{b r a s s} = 18 \times 10^{- 6} K^{- 1}

0^{o} C

(α_{b r a s s} = 12 \times 10^{- 6}^{o} C^{- 1}, α_{s t e e l} = 17 \times 10^{- 6}^{o} C^{- 1})

100 c m

5 m m

α

= 12 \times 10^{- 6}^{o} C^{- 1})

Join BYJU'S Learning Program