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Question

A man with blood group B marries a female with blood group A and their first child is having blood B. What is the genotype of child

A
IAIB
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B
IAIO
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C
IBIO
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D
IBIB
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Solution

The correct option is C IBIO
Human blood group inheritance is the example of codominance and multiple alleles. It is governed by three alleles namely IA, IB and IO. IA and IB show codominance while allele IO is recessive to both IA and IB. This gives total six genotypes and four phenotypes- A (IA IA and IA IO), B (IB IB and IB IO) , AB (IA IB) and O (IO IO). Since the mother has A blood group, the child can not be homozygous for B blood group. The reason is that he will receive one IB allele from father with B blood group but the mother with A blood group can transmit only IO allele for the child to have B blood group. Hence the genotype of child will be IB IO. Option D is incorrect and C is correct. Genotypes in options A and B gives AB and A blood groups respectively which makes them wrong.

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