wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A man with blue eyes and black hair (homozygous for both characters) marries a woman with
black eyes and red hair. Black eyes (E) are dominant over blue eyes (e) and black hair (H) is dominant over red hair (h). Work out the probabilities of phenotypes of the children of this couple using punnett square method.

Open in App
Solution

The man with blue eyes and black hair will have the genotype eeHH (as homozygous for both characters) while the woman with black eyes and red hair may have the genotype EEhh or Eehh. Let's first consider her to be EEhh. Then their progeny genotypes can be calculated as follows:
Eh Eh
eH EeHh EeHh
eH
EeHh

EeHh


Thus, all their progeny will have black eyes and black hair. The probability of phenotypes of the progeny in second case can be worked out in a similar manner.

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Mendel's Experiments
BIOLOGY
Watch in App
Join BYJU'S Learning Program
CrossIcon