A manganin wire of length 2 m has a diameter of 0-4 mm with a resistance of 70- Find the resistivity of the material-

Resistivity =ρ = RA l #160; #160; = 70×π×( 0.2× 10 ^ 3 ) #160;^ 2 2 #160; #160; =4.396× 10 ^ 6 Ω m ...

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Standard X

Physics

Resistivity

A manganin wi...

Question

A manganin wire of length $2 m$ has a diameter of $0.4 m m$ with a resistance of $70 Ω$ . Find the resistivity of the material.

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Solution

Resistivity $= ρ = \frac{R A}{l}$
$= \frac{70 \times π \times {(0.2 \times 10^{- 3})}^{2}}{2}$
$= 4.396 \times 10^{- 6} Ω m$

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A manganin wire of length 2m has a diameter of 0.4mm with a resistance of 70Ω. Find the resistivity of the material.

Resistivity=ρ=RAl =70×π×(0.2×10−3)22 =4.396×10−6Ωm

A manganin wire of length $2 m$ has a diameter of $0.4 m m$ with a resistance of $70 Ω$ . Find the resistivity of the material.

Resistivity $= ρ = \frac{R A}{l}$
$= \frac{70 \times π \times {(0.2 \times 10^{- 3})}^{2}}{2}$
$= 4.396 \times 10^{- 6} Ω m$