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Question

A manufacturer accidentally dropped some industrial diamonds into copper (II) oxide powder. Which steps could be used to recover the diamonds from the mixture?

A
Step I: Shake with dilute sulphuric acid; Step II: Filter; Step III: Evaporate the filtrate to dryness
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B
Step I: Shake with dilute sulphuric acid; Step II: Filter; Step III: Save the residue and wash it with water
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C
Step I: Shale with water; Step I: Filter; Step III: Save the residue and wash it with water
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D
Step I: Shake with water; Step II: Filter; Step III: Evaporate the filtrate to dryness
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Solution

The correct option is B Step I: Shake with dilute sulphuric acid; Step II: Filter; Step III: Save the residue and wash it with water
Copper (ii) oxide is insoluble in water. When it is reacted with dilute sulphuric acid, it forms copper sulphate as the blue colour solution (soluble). The reaction can be written as follows,
CuO(s)+H2SO4(dil)CuSO4(aq)+H2O(l)

Diamond remain insoluble on reaction with dilute sulphuric acid and it formed as residue. Then, the blue colour copper sulphate solution has to be filtered and the residue will then washed with water to recover diamonds from the mixture.
Thus, option - B is correct.

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