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Standard VIII

Mathematics

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A manufacture...

Question

A manufacturer makes two types of toys $A$ and $B$ . Three machine are needed for this purpose and the time (in minutes) required for each toy on the machines is given below:
How many toys can be made in $1 h r$ if the two types are made paralelly.

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Solution

Time taken for $A$ type toy $20 + 10 + 10 = 40 M i n$
Time taken for $B$ type toy $10 + 20 + 30 = 60 M i n$
So only one toy of each type can be done in $1 h r$

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Each machine is available for a maximum of 6 h per day. If the profit on each toy of type A is Rs.7.50 and that the each toy of type B is Rs. 5, show that 15 toys of type A and 30 of type B should be manufactured in a day to get maximum profit.

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A manufacturer makes two types of toys A and B . Three machine are needed for this purpose and the time (in minutes) required for each toy on the machines is given below:How many toys can be made in 1hr if the two types are made paralelly.

Time taken for A type toy 20+10+10=40MinTime taken for B type toy 10+20+30=60MinSo only one toy of each type can be done in 1hr

A manufacturer makes two types of toys $A$ and $B$ . Three machine are needed for this purpose and the time (in minutes) required for each toy on the machines is given below:
How many toys can be made in $1 h r$ if the two types are made paralelly.

Time taken for $A$ type toy $20 + 10 + 10 = 40 M i n$
Time taken for $B$ type toy $10 + 20 + 30 = 60 M i n$
So only one toy of each type can be done in $1 h r$