Question

A manufacturing company finds out the number of defective calculators in each of the last $10$ batches of $100$ calculators.


The mean number of defective calculators with outlier is and without outlier is .

Answer 1

From the given data set, we observe that in the batch number $10$, the number of defective calculators is $98$ out of $100$ calculators. As something goes terribly wrong in this batch number $10$, we can consider $98$ defective calculators as an outlier here.

We know,
$\text{Mean of a data set}=\frac{\text{Sum of all data points}}{\text{Total number of data points}}$

$\bullet$ The mean number of defective calculators with outlier is

$\frac{23+34+43+13+45+27+38+42+16+98}{10}$
$=\frac{379}{10}=37.9$

$\bullet$ The mean number of defective calculators without outlier is

$\frac{23+34+43+13+45+27+38+42+16}{9}$

$=\frac{281}{9}=31.2\overline{2}$