Question

A marble block of mass $2kg$ lying on ice when given a velocity of $6m/s$ is stopped by friction in $10s$. Then the coefficient of friction is

• A. $0.01$
• B. $0.02$
• C. $0.03$
• D. $0.06$

Answer 1

The correct option is D $0.06$

As we know that,
$v=u+at\Rightarrow u-at=0$
$a=\frac{6}{10}\Rightarrow a=-0.6m/s^2$($-ive$ means retardation)
As block is stoped due to friction so,
$F_{friction}=ma$
$\mu \left(mg\right)=m\times 0.6$
$\mu =\frac{0.6}{10}=0.06$