Question

A marble block of mass $2kg$ lying on ice when given a velocity of $6m/s$ is stopped by friction in $10s$. Then the coefficient of friction is

• A. $0.01$
• B. $0.02$
• C. $0.03$
• D. $0.06$

Answer 1

The correct option is D $0.06$

By the first equation of motion
$v=u+at$ and as the block decelerates before stopping
and final velocity $v=0$
$v=u-at\Rightarrow u-\mu gt=0$
$\therefore \mu =\frac{u}{gt}=\frac{6}{10\times 10}=0.06$