A marble block of mass 2kg lying on the ice, when given a velocity of 6m/s is stopped by friction in 10s. Then find the value of the coefficient of friction if g=10m/s2.
A
0.01
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B
0.02
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C
0.03
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D
0.06
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Solution
The correct option is D0.06 The given situation can be reframed as shown below
Let the coefficient of the friction be μ
Therefore, friction force acting on block, f=μmg=2μg
So, from the FBD we have a=fm=−2μg2=−μg
Since, retardation takes place here, we have taken acceleration a as −ve
So, from the equation of motion we have v=u+at
Since the blocks finally comes to rest, ⇒0=u−μgt ∴μ=ugt=610×10=0.06