Question

A marble block of mass 2kg lying on ice when given a velocity of $6m{s}^{-1}$ is stopped by friction in 10s. Then the coefficient of friction is ( Take $g=10m{s}^{-2}$)

• A. 0.06
• B. 0.03
• C. 0.04
• D. 0.01

Answer 1

The correct option is A 0.06

$a=\mu g=\frac{6}{10}$ [using v=u+at]

$\Rightarrow \mu =\frac{6}{10\times g}=\frac{6}{10\times 10}=0.06$