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Question
A marble going at a speed of 12ms−1 hits another marble of equal mass at rest. If the collision is perfectly elastic. Find the velocity of the first after collision.
A marble going at a speed of 12ms−1 hits another marble of equal mass at rest. If the collision is perfectly elastic. Find the velocity of the first after collision.
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Solution
The correct option is B 0
m(12)+m(0)=mv1+mv2=0⇒v1+v2=12
−v1−v212−(0)=1⇒v1−v2=−12
thus,v1=0v2=12,sovelocityoffirstaftercollisionis0.
m(12)+m(0)=mv1+mv2=0⇒v1+v2=12
−v1−v212−(0)=1⇒v1−v2=−12
thus,v1=0v2=12,sovelocityoffirstaftercollisionis0.
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