A marble travelling at $100 c m / s$ rolls of the edge of a level table. It hits the floor $30 c m$ away from the spot directly below the edge of the table. Height of the table is ( $g = 9.8 m / s^{2}$ )

44 c m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

100 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

30 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

70 c m

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $44 c m$
Range $= 30$ cm
$u = 100$ cm/s
time $= \frac{R}{u} = \frac{30}{100} = 0.3$ sec
$u_{v} = 0; a = - 9.8 m / s^{2}$
$S = \frac{1}{2} \times (- 9.8) . (3)^{2} = 4.4 m = 44$ cm

Suggest Corrections

Similar questions

Q. A marble with speed 20 cm/s rolls off the edge of a table 80 cm high. How far horizontally from the table edge does the marble strike the floor? (answer in

cm

and take

g = 10 m / s^{2}

)

Q. A marble with speed 20 cm/s rolls off the edge of a table 80 cm high. How far horizontally from the table edge does the marble strike the floor? (answer in

cm

and take

g = 10 m / s^{2}

)

A marble with speed 20 cm/s rolls off the edge of a table 80 cm high. How long does it take to drop to the floor? How far horizontally from the table edge does the marble strike the floor?

Q. A ball rolls off the edge of a horizontal table top 4m high. If it strikes the floor at a point 5 m horizontally away from the edge of the table, what was its speed at the instant it left the table.

___

Q. A ball is rolled off the edge of a horizontal table at a speed of 4 m/s. It hits the ground after 0.4 second. Which statement given below is true(Take

g = 10 m / s^{2}

)

Join BYJU'S Learning Program

A marble travelling at 100 cm/s rolls of the edge of a level table. It hits the floor 30 cm away from the spot directly below the edge of the table. Height of the table is (g=9.8 m/s2)

The correct option is A 44 cmRange =30 cmu=100 cm/stime =Ru=30100=0.3 secuv=0; a=−9.8m/s2S=12×(−9.8).(3)2=4.4m=44 cm

A marble travelling at $100 c m / s$ rolls of the edge of a level table. It hits the floor $30 c m$ away from the spot directly below the edge of the table. Height of the table is ( $g = 9.8 m / s^{2}$ )

The correct option is A $44 c m$
Range $= 30$ cm
$u = 100$ cm/s
time $= \frac{R}{u} = \frac{30}{100} = 0.3$ sec
$u_{v} = 0; a = - 9.8 m / s^{2}$
$S = \frac{1}{2} \times (- 9.8) . (3)^{2} = 4.4 m = 44$ cm