Question

A mark at the bottom of a beaker containing liquid appears to rise by $0.1m.$ The depth of the liquid is $1m.$ The refractive index of liquid is:

• A. $1.33$
• B. $\frac{9}{10}$
• C. $\frac{10}{9}$
• D. $1.5$

Answer 1

Answer: (C)

$\frac{10}{9}$

Given: A mark at the bottom of a beaker containing liquid appears to rise by $0.1m$. The depth of the liquid is $1m$.

To find the refractive index of liquid.

Solution:

As per the given condition,

Real depth of the liquid= $1m$

Apparent depth of the liquid =$1-0.1=0.9m$

Refractive index of the liquid = $\frac{\text{Real Depth}}{\text{Apparent Depth}}=\frac{1}{0.9}=\frac{10}{9}$