A mark is made on the bottom of a beaker and a microscope is focused on it . The microscope is raised through 1.5 cm . To what height water must be poured into the beaker to bring the mark again into focus ? Given that 'n' is 4/3

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Solution

Here we want to find real depth.

using formula,

seperation = real depth – apparent depth

apparent depth = real depth /n .

So separation=1.5=real depth - (real depth÷n)

So Separation,1.5= (Rd) -(Rd÷(4÷3))=Rd-(3÷4)Rd

=(1÷4)Rd

Rd=4×1.5=6 cm rd means real depth... so answer is 6cm

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A mark is made on the bottom of a beaker and a microscope is focused on it . The microscope is raised through 1.5 cm . To what height water must be poured into the beaker to bring the mark again into focus ? Given that 'n' is 4/3

Here we want to find real depth. using formula, seperation = real depth – apparent depth apparent depth = real depth /n . So separation=1.5=real depth - (real depth÷n) So Separation,1.5= (Rd) -(Rd÷(4÷3))=Rd-(3÷4)Rd =(1÷4)Rd Rd=4×1.5=6 cm rd means real depth... so answer is 6cm

Here we want to find real depth.

using formula,

seperation = real depth – apparent depth

apparent depth = real depth /n .

So separation=1.5=real depth - (real depth÷n)

So Separation,1.5= (Rd) -(Rd÷(4÷3))=Rd-(3÷4)Rd

=(1÷4)Rd

Rd=4×1.5=6 cm rd means real depth... so answer is 6cm