A mark is made on the bottom of a vessel, over this mark a glass slab of thickness 3.5 cm and refractive index 7/4 is placed. Now water (refractive index 4/3) is poured into the vessel so that the surface of water is 8 cm above the upper surface of the slab. Looking down normally through the water, the apparent depth of the mark below the surface of water will be

6.33 cm

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8 cm

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7.5 cm

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10 cm

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Solution

The correct option is B
8 cm

Refractive index = real depth / apparent depth.

Apparent depth = {8 / (4/3)} + {3.5 / (7/4)} = 6 + 2 = 8 cm

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Q. A mark is made on the bottom of a vessel and over this mark, a glass slab to thickness 3.5 cm and refractive index

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The correct option is B 8 cm Refractive index = real depth / apparent depth. Apparent depth = {8 / (4/3)} + {3.5 / (7/4)} = 6 + 2 = 8 cm

The correct option is B
8 cm

Refractive index = real depth / apparent depth.

Apparent depth = {8 / (4/3)} + {3.5 / (7/4)} = 6 + 2 = 8 cm