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Standard XII

Physics

Friction and Vertical Circular Motion Problems

A mass 0.1 ...

Question

A mass $0.1 k g$ is rotated in a vertical circle using the cord of length $1 m$ , when the cord makes an angle $60^{0}$ with the vertical, the speed of the mass is $3 m / s$ the resultant radial acceleration of mass in that position is:

9 m / s^{2}

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4.9 m / s^{2}

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4.1 m / s^{2}

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zero

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Solution

The correct option is C $4.1 m / s^{2}$
Radial acceleration at that position , $a_{r} = \frac{v^{2}}{r} - g c o s θ$
$a_{r} = 9 - 4.9 = 4.1 m / s^{2}$

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A mass 0.1 kg is rotated in a vertical circle using the cord of length 1 m, when the cord makes an angle 600 with the vertical, the speed of the mass is 3 m/s the resultant radial acceleration of mass in that position is:

The correct option is C 4.1m/s2Radial acceleration at that position , ar=v2r−gcosθar=9−4.9=4.1 m/s2

A mass $0.1 k g$ is rotated in a vertical circle using the cord of length $1 m$ , when the cord makes an angle $60^{0}$ with the vertical, the speed of the mass is $3 m / s$ the resultant radial acceleration of mass in that position is:

The correct option is C $4.1 m / s^{2}$
Radial acceleration at that position , $a_{r} = \frac{v^{2}}{r} - g c o s θ$
$a_{r} = 9 - 4.9 = 4.1 m / s^{2}$