Question

A mass $1kg$ suspended from a spring whose force constant is $400N/m,$ executes simple harmonic oscillation . When the total energy of the oscillation is $2J$ , the maximum acceleration experienced by the mass will be

• A. $2m/s^2$
• B. $4m/s^2$
• C. $40m/s^2$
• D. $400m/s^2$

Answer 1

The correct option is C $40m/s^2$

Energy stored =work done
$E=\frac{1}{2}k{r}^2$
$r=\sqrt{\frac{2E}{K}}$
$\sqrt{\frac{2\times 2}{400}}=\frac{1}{10}m$
$\alpha ={\omega }^{2}r=(\sqrt{k}m{)}^2\times \frac{1}{10}$
$=\left(\frac{400}{1}\right)\times \frac{1}{10}=40m/s^2$