A mass 2 kg supported by a massless string wound around a uniform hollow cylinder of mass 2 kg and radius 1 m. If the string does not slip on the cylinder, then acceleration of mass is -
A
7 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
5 m/s2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
10 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
8 m/s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is B5 m/s2 Let us suppose acceleration of mass is a According to question -
on applying ∑F=ma for mass 20−T=2a−−−−(1) on applyiing ∑T=Iα for hollow cylinder 1×T=2×12×α[∵T=r⊥F=Iα,I=mR2] ⇒T=2×a1[a=αR] ⇒T=2a−−−−(2) On adding (1) and (2) 20=4a ⇒a=5 m/s2 Acceleration of the mass is 5 m/s2