A mass is attached to a spring balance which is kept in a lift. The lift accelerates upwards. The spring balance will show in its readings

an increase

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

a decrease

No worries! We‘ve got your back. Try BYJU‘S free classes today!

no change

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a change depending on its velocity

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A an increase
Let acceleration of lift $= a$ and
Let reaction at spring balance $= R$
Applying Newton's law
$R - m g = m a \Rightarrow R = m (g + a)$
thus net weight increases, so reading of spring balance increases.

Suggest Corrections

Similar questions

Q. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring balance reads 49 N, when the lift is stationary. Determine the reading of the spring balance, if the lift moves downward with an acceleration of 5

m s^{- 2}

An object is suspended from a spring balance in a lift. The reading is 240 N when the lift is at rest. If the spring balance reading now changes to 220 N, then the lift is moving

Q. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads

49 N

, when the lift is stationary. If the lift moves downward with an acceleration of

5 {m/s}^{2}

, the reading of the spring balance ( in

N

) will be

Q. A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads

49 N

, when the lift is stationary. If the lift moves downward with an acceleration of

5 {m/s}^{2}

, the reading of the spring balance ( in

N

) will be

A spring balance is attached to the ceiling of a lift. A man hangs his bag on the spring and the spring reads 49 N, when the lift is stationary. If the lift moves downward with an acceleration of $5 m / s^{2}$ , the reading of the spring balance will be:

Join BYJU'S Learning Program

A mass is attached to a spring balance which is kept in a lift. The lift accelerates upwards. The spring balance will show in its readings

The correct option is A an increaseLet acceleration of lift =a and Let reaction at spring balance =R Applying Newton's law R−mg=ma⇒R=m(g+a) thus net weight increases, so reading of spring balance increases.

The correct option is A an increase
Let acceleration of lift $= a$ and
Let reaction at spring balance $= R$
Applying Newton's law
$R - m g = m a \Rightarrow R = m (g + a)$
thus net weight increases, so reading of spring balance increases.