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Question

A mass is suspended from the end of a spring. When the system is oscillating the amplitude of oscillation is 4 cm and the maximum kinetic energy of oscillation of the system is 1 joule. Then the force constant of the spring is:

A
2500 N/m
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B
1250 N/m
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C
500 N/m
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D
250 N/m
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Solution

The correct option is A 1250 N/m
By energy conservation, maximum kinetic energy is equal to the potential energy of the spring at maximum elongation since kinetic energy is zero at maximum elongation.

Hence, 1=12k(0.04)2

k=1250 N/m



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